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A spherical ball A of mass 4 kg, moving ...

A spherical ball A of mass 4 kg, moving along a straight line strikes another spherical ball B of mass 1 kg at rest. After the collision, A and B move with velocities `v_1 m s^(-1) and v_2 m s^(-1)` respectively making angles of `30^@ and 60^@` with respect to the original direction of motion of A. The ratio `v_1/v_2` will be

A

`sqrt3/4`

B

`4/sqrt3`

C

`1/sqrt3`

D

`sqrt3`

Text Solution

Verified by Experts

The correct Answer is:
A

Applying the law of conservation of linear momentum along a direction perpendicular to the direction of motion (i.e. along y-axis), we get
`0+0 = 4v_1 sin30^@- v_2 sin60^@`
`4v_1 sin30^@ = v_2 sin60^@ or v_1/v_2 =(sin 60^@)/(4sin 30^@)=sqrt3/4`
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