The graph between two temperature scales `A` and `B` is shown in Fig. Between upper fixed point and lower fixed point there are `150` equal divisions on scales `A` and `100` on scale `B`. The relation between the temperature in two scales is given by_

Options

A. `(T_(A) - 180)/(100) = (T_(B))/(150)`
B. `(T_(A) - 30)/(150) = (T_(B))/(100)`
C. `(T_(B) - 180)/(150)= (T_(A))/(100)`
D. `(T_(B) - 40)/(100) = (T_(A))/(180)`

Answer

B

Explanation

For the graph
For the scale A,
Lower fixed point `= 30^(@)A`
Upper fixed point `= 180^(@)A`
For the scale ` B` ,
Lower fixed point `= 0^(@)B`
Upper fixed point `= 100^(@)B`
`:.` The relationship between the two scales A an B is given by
`(T_(A) - 30) /(150) = (T_(B) - 0)/(100) = (T_(B))/(100)`