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A heater coil is rated 100W,200V. It is ...

A heater coil is rated 100W,200V. It is cut into two identical parts. Both parts are connected together in parallel, to the same sources of 200V. Calculate the energy liberated per second in the new combination.

A

100J

B

200J

C

300J

D

400J

Text Solution

Verified by Experts

The correct Answer is:
D
Resistance of heater coil,
`R=(V^(2))/(P)=(200xx200)/(100)=400Omega`
Resistance of either half part=`200Omega`
Equivalent resistance when both parts are connected in parallel.
`R'=(200xx200)/(200+200)=100Omega`
Energy liberated per second when combustion in connected to a source of 200V.
`=(V^(2))/(R')=(200xx200)/(100)=400J`
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