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If n cells each of emf E and internal re...

If n cells each of emf E and internal resistance are connected in parallel, then the total emf and internal resistances will be

A

`epsi, (r)/(n)`

B

`epsi,nr`

C

`"n"epsi,(r)/(n)`

D

`"n"epsi,nr`

Text Solution

Verified by Experts

The correct Answer is:
A

In the parallel combination, `(epsi_("eq"))/(r_("eq"))=(epsi_(1))/(r_(1))+(epsi_(2))/(r_(2))+,.....+(epsi_(n))/(r_(n))`
`(1)/(r_("eq"))=(1)/(r_(1))+(1)/(r_(2))+...+(1)/(r_n)`
`(therefore epsi_(1)=epsi_(2)=epsi_(3)=.....=epsi_(n)=epsi and r_(1)=r_(2)=r_(3)=r...r_(n)=r)`
`therefore (epsi_("eq"))/(r_("eq))=(epsi)/(r)+(epsi)/(r)+......+(epsi)/(r)=n(epsi)/(r)..(i)`
`(1)/(r_("eq"))=(1)/(r)+(1)/(r)+....+(1)/(r)=(n)/(r)`
`r_("eq")=r//n...(ii)`
From (i) and (ii)
`e_("eq")=n(epsi)/(r)xxr_("eq")=nxx(epsi)/(r)xx(epsi)/(n)=epsi`
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