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The potentiometer wire of length 200 cm ...

The potentiometer wire of length `200 cm` has a resistance of `20 Omega`. It is connected in series with a resistance `10 Omega` and an accumulator of emf `6 V` having negligible internal resistance. A source of `2.4 V` is balanced against length `1` of the potentiometer wire. Find the length `l` of the potentiometer wire. Find the length `l`

A

100cm

B

120cm

C

110cm

D

140cm

Text Solution

Verified by Experts

The correct Answer is:
B
The current in the potentiometer wire AB is `I=(6)/(20+10)=0.2A`
The potential difference across the potential wire is
`V="current"xx"resistance"=0.2xx20=4V`
The length of the wire is l=200 cm, So, the potential gradient along the wire is `k=(V)/(l)=(4)/(200)=0.02Vcm^(-1)`
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