A alternating voltage given by `V = 140 sin 314 t` is connected across a pure resistor of 50 ohm. Find the rms current through the resistor.

Options

A. `1.98 A`
B. `5.63 A`
C. `3.536 A`
D. `49.39 A`

Answer

A

Explanation

Here, `R = 50 Omega, V_(0)=140V`
`therefore I_("rms")=(V_("rms"))/(R )=(0.707V_(0))/(R )=(0.707xx140)/(50)=1.98 A`.