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In a pure capacitive circuit if the freq...

In a pure capacitive circuit if the frequency of ac source is doubled, then its capacitive reactance will be

A

remains same

B

doubled

C

halved

D

zero

Text Solution

Verified by Experts

The correct Answer is:
C
Capacitive reactance, `X_(C )=(1)/(2pi upsilon C)`
`rArr X_(C ) prop (1)/(upsilon) therefore (X_(C_(1)))/(X_(C_(2)))=(upsilon_(2))/(upsilon_(1))=(2upsilon)/(upsilon)=2`
`rArr X_(C_(2)) = (X_(C_(1)))/(2)`
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Knowledge Check

  • In a purely capacitive circuit, the current

    A
    lead the applied emf by `pi//2`
    B
    lags behind of applied emf by `pi//2`
    C
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  • In a purely capacitive ac circuit, the value of current is:

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    B
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    C
    `i_(m) sin (omega t + (pi)/(2))`
    D
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  • With an increase in the frequency of an AC supply the capacitive reactance

    A
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    B
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    C
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    D
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