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An ac source is of (200)/(sqrt(2))V, 50 ...

An ac source is of `(200)/(sqrt(2))V`, `50 Hz`. The value of voltage after `(1)/(600)s` from the start is

A

`200 V`

B

`(200)/(sqrt(2))V`

C

`100 V`

D

`50 V`

Text Solution

Verified by Experts

The correct Answer is:
C

`V_("rms")=(200)/(sqrt(2))V`
`V_(0)=sqrt(2)xx(200)/(sqrt(2))=200 V`
`V=V_(0)sin 2pi upsilon t=200 sin (2pixx50xx(1)/(600))`
`=200 "sin"(pi)/(6)=200xx(1)/(2)=100 V`
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