Home
Class 12
PHYSICS
An ac source of voltage V=V(m)sin omega ...

An ac source of voltage `V=V_(m)sin omega t` is connected across the resistance R as shown in figure. The phase relation between current and voltage for this circuit is

A

both are in phase

B

both are out of phase by `90^(@)`

C

both are out of phase by `120^(@)`

D

both are out of phase by `180^(@)`

Text Solution

Verified by Experts

The correct Answer is:
A

The given circuit is a pure resistive circuit. In this circuit the voltage and current both are in phase.
Promotional Banner

Topper's Solved these Questions

  • ALTERNATING CURRENT

    NCERT FINGERTIPS|Exercise Ac Voltage Applied To A Inductor|5 Videos
  • ALTERNATING CURRENT

    NCERT FINGERTIPS|Exercise Ac Voltage Applied To A Capacitor|12 Videos
  • ATOMS

    NCERT FINGERTIPS|Exercise Assertion And Reason|15 Videos

Similar Questions

Explore conceptually related problems

An ac source of voltage V = V_ 0sin omegat is connected to a series combination of L, C and R. Use the phasor diagram to obtain expressions for impedance of the circuit and phase with the voltage. What is circuit in this condition called?

An AC voltage source V=V_0siomegat is connected across resistance R and capacitance C as shown in figureure. It is given that R=1/omegaC . The peak current is I_0 . If the angular frequency of the voltage source is changed to omega/sqrt3, then the new peak current in the circuit is .

A 50 Hz AC source of 20 V is connected across R and C as shown in figureure. The voltage across R is 12 V . The voltage across C is

An a.c. source generating a voltage v=v+(m) sin omega t is connected to a capacitor of capacitor of capacitance C. Find the expression for the current, I, flowing through it. Plot a graph of v and I versus omega t to show that the current is pi//2 ahead of the voltage. A resistor of 200 Omega and a capacitor of 15.0 mu F are connected in series to a 220 V, 50 Hz a.c. source. Calculate the current in the circuit and the rms voltage across the resistor and the capacitor. Is the algebraic sum of these voltages more than the source voltages ? If yes, resolve the paradox.

In an AC circuit, voltage V = V_(0)sin omegat and inductor L is connected across the circuit. Then the instantaneous power will be

NCERT FINGERTIPS-ALTERNATING CURRENT -Assertion And Reason
  1. An ac source of voltage V=V(m)sin omega t is connected across the resi...

    Text Solution

    |

  2. Assertion : An alternating current does not show any magnetic effect. ...

    Text Solution

    |

  3. Assertion: Average value of AC over a complete cycle is always zero. ...

    Text Solution

    |

  4. Assertion : The capacitive reactance limits the amplitude of the curre...

    Text Solution

    |

  5. Assertion : The inductive reactance limits amplitude of the current in...

    Text Solution

    |

  6. Assertion : In series LCR resonance circuit, the impedance is equal to...

    Text Solution

    |

  7. Assertion : In a purely inductive or capacitive circuit, the current i...

    Text Solution

    |

  8. Assertion : The only element that dissipates energy in an ac circuit i...

    Text Solution

    |

  9. Assertion : The power in ac circuit is minimum if the circuit has only...

    Text Solution

    |

  10. Assertion : Resonance is exhibited by a circuit only if both L and C a...

    Text Solution

    |

  11. Assertion : When a current flows in the coil of a transformer then its...

    Text Solution

    |

  12. Assertion : An ideal transformer does not vary the power. Reason : A...

    Text Solution

    |

  13. Assertion : A step-up transformer changes a low voltage into a high vo...

    Text Solution

    |

  14. Assertion : A given transformer can be used to step-up to step-down th...

    Text Solution

    |

  15. Assertion : A laminated core is used in transformers to increase eddy ...

    Text Solution

    |

  16. Assertion : A transformer cannot work on dc supply. Reason : dc chan...

    Text Solution

    |