In series LCR circuit, the plot of `I_("max")` versus `omega` is shown in figure. Find the bandwith and mark in the figure.

Options

A. zero
B. `0.1 "rad "s^(-1)`
C. `0.2 "rad "s^(-1)`
D. `0.4 "rad "s^(-1)`

Answer

D

Explanation

Bandwidth is the frequency range at which current amplitude `I_(m)=(1)/(sqrt(2))I_("max")=0.7 I_("max")`

From figure,
Band width `Delta omega = 1.2-0.8=0.4" rad " s^(-1)`