In the given figure ABCD is a trapezium in which `AB||DC, AB=18cm, DC=32cm` and the distance between AB and DC is 14 cm. If arcs of equal radii 7 cm hav been drawn with centres A,B,C and D then find the area of the shaded region.
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Given, AB = 18cm, DC = 32 cm, height, (h) = 14cm and arc of radii = 7 cm Since, AB || DC `:. angleA + angleD = 180^(@)` and `angleB + angleC = 180^(@)` `:.` Area of sector with angle A and `D = (thetaxxpir^(2))/(360)` =`(180^(@))/(360)xx(22)/(7)xx(7)^(2)` = `11xx7 = 77cm^(2)` similarly, area of sector with angle B and C = 77cm Now, area of trapezium = `(1)/(2)(AB + DC) xxh` = `(1)/(2)(18+32)xx14=(50)/(2)xx14= 350cm^(2)` `:.` Area of shaded region = Area of trapezium - (Area of sector points A and D + Area of sector points B and C) = `350 - (77+ 77) = 196 cm^(2)` Hence, the required area of shaded region is `196 cm^(2)` .
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