Floor of a room is of dimensions ` 5mxx4m` and it is covered with circular tiles of diameters 50 cm each as shown infigure . Find area of floor that remains uncovered with tiles. (use `pi= 3.14`)

Explanation

Given, floor of a room is covered with circular tiles.
Length of a floor of a room (l) = 5m
and breadth of floor of a room (b) = 4m
`:.` Area of floor of a room = `lxxb`
= ` 5xx4= 20 m^(2)`
Diameter of each circular tile = 50 cm
`rArr` Redius of each circular tile = `(50)/(2)=25 cm`
= `(25)/(100) m =(1)/(4)m`
Now, area of a circular tile = `pi ("radius")^(2)`
= ` 3.14xx((1)/(4))^(2) = (3.14)/(16)m^(2)`
`:.` Area of 80 circular tiles = `80xx(3.14)/(16)= 5xx3.14 = 15.7 m^(2)` [`because` 80 congruent circular tiles covering the floor of a room]
So, area of floor that remains uncovered with tiles = Area of floor of a room - Area of 80 circular tiles
= `20 - 15.7 = 4.3 m^(2)`
Hence, the required area of floor that remains uncovered with tiles is `4.3 m^(2)` .