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If x=(1)/(sqrt(3)+sqrt(2)). Then find (1...

If `x=(1)/(sqrt(3)+sqrt(2))`. Then find `(1)/(x)`.

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To find \( \frac{1}{x} \) where \( x = \frac{1}{\sqrt{3} + \sqrt{2}} \), we can follow these steps: ### Step 1: Write the expression for \( \frac{1}{x} \) Given that \( x = \frac{1}{\sqrt{3} + \sqrt{2}} \), we can express \( \frac{1}{x} \) as: \[ \frac{1}{x} = \sqrt{3} + \sqrt{2} \] ### Step 2: Rationalize the denominator of \( x \) To find \( \frac{1}{x} \) in a more simplified form, we can rationalize the denominator of \( x \): \[ x = \frac{1}{\sqrt{3} + \sqrt{2}} \cdot \frac{\sqrt{3} - \sqrt{2}}{\sqrt{3} - \sqrt{2}} = \frac{\sqrt{3} - \sqrt{2}}{(\sqrt{3} + \sqrt{2})(\sqrt{3} - \sqrt{2})} \] ### Step 3: Simplify the denominator Now, we simplify the denominator: \[ (\sqrt{3} + \sqrt{2})(\sqrt{3} - \sqrt{2}) = 3 - 2 = 1 \] Thus, we have: \[ x = \sqrt{3} - \sqrt{2} \] ### Step 4: Find \( \frac{1}{x} \) Now that we have \( x \) simplified, we can find \( \frac{1}{x} \): \[ \frac{1}{x} = \frac{1}{\sqrt{3} - \sqrt{2}} \] ### Step 5: Rationalize \( \frac{1}{x} \) To rationalize \( \frac{1}{x} \): \[ \frac{1}{x} = \frac{\sqrt{3} + \sqrt{2}}{(\sqrt{3} - \sqrt{2})(\sqrt{3} + \sqrt{2})} = \frac{\sqrt{3} + \sqrt{2}}{3 - 2} = \sqrt{3} + \sqrt{2} \] ### Final Result Thus, the value of \( \frac{1}{x} \) is: \[ \frac{1}{x} = \sqrt{3} + \sqrt{2} \] ---

To find \( \frac{1}{x} \) where \( x = \frac{1}{\sqrt{3} + \sqrt{2}} \), we can follow these steps: ### Step 1: Write the expression for \( \frac{1}{x} \) Given that \( x = \frac{1}{\sqrt{3} + \sqrt{2}} \), we can express \( \frac{1}{x} \) as: \[ \frac{1}{x} = \sqrt{3} + \sqrt{2} \] ...
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