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This triangular side walls of a flyover...

This triangular side walls of a flyover have been used for advertisements. This sides of the walls are `122 m, 22m` and `120 m` (see figure). The advertisements yield an earning of `Rs. 500` per `m^(2)` per year. A company hired one of its walls for `3` months. How much rent did it pay ?

A

`Rs. 16,50,000`

B

`Rs. 16,00,000`

C

`Rs. 16,80,000`

D

`Rs. 16,65,000`

Text Solution

Verified by Experts

The correct Answer is:
A
Let `a = 122 m , b = 22 m, c = 120 m`
We have , `b^(2) +c^(2)= (22)^(2) +(120)^(2) = 484 + 14400 = 14884 = (122)^(2)= a^(2)`
Hence, the side walls are in right triangled shape.
The area of the triangular side walls = `((1)/(2)xxaxxc)`
`=((1)/(2) xx22xx120)=11xx120`
`= 1320 m^(2)`
Now `" "` yearly rent = Rs. 5000 per `m^(2)`
`:. " " ` Monthly rent `=Rs. 5000 xx(1)/(12) ` per `m^(2)`
Company hired one of its walls for 3 months.
Thus, rent paid by the company for 3 months `=Rs. 1320xx (5000)/(12)xx3`
`=110xx5000xx3`
` = Rs. 1650000`
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