Convert the following in the form of `(a+ib)` :
(i) `(1+i)^(4)`
(ii) `(-3+(1)/(2)i)^(3)`
(iii) `(1-i)(3+4i)`
(iv) `(1+i)(1+ 2i)(1+ 3i)`
(v) `(3+5i)/(6-i)`
(vi) `((2+3i)^(2))/(2+i)`
(vii) ` ((1+ i)(2+i))/((3+i))`
(viii) ` (2-i)^(-3)`

Answer

N/a

Explanation

(i) `- 4+ 0*i`
(ii) `-(99)/(4)+(107i)/(8)`
(iii) `7+i`
(iv) `-10+0*i`
(v) `(13)/(37)+(33)/(37)i`
(vi) `(2)/(5)+(29)/(5)i`
(vii) `(3)/(5)+(4)/(5)i`
(viii) `(2)/(125)+(11)/( 125)i`