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If alpha!= beta but alpha^2 = 5alpha-3, ...

If `alpha!= beta` but `alpha^2 = 5alpha-3, beta^2 = 5beta - 3`, then find the equation whose roots are `alpha/beta and beta/alpha`.

A

`3x^(2)-19x-3=0`

B

`3x^(2)-19x+3=0`

C

`3x^(2)+19x+3=0`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B
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