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If (1)/(6!) +(1)/(7!) = (x)/(8!), find x...

If `(1)/(6!) +(1)/(7!) = (x)/(8!)`, find x.

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`(1)/(6!) + (1)/(7!) = (x)/(8!)`
`rArr x = 8! ((1)/(6!)+(1)/(7!))= (8!)/(6!) +(8!)/(7!)`
`=(8 xx 7 xx 6!)/(6!) +(8 xx 7!)/(7!)`
` = 56 +8 = 64`
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