It is required to seat 5 men and 4 women in a row so that thatr women occupy the even places. How many such arrangement are possible?

Explanation

There will be 5 odd places and 4 even places while 5 men and 4 women seat in a row.
No. of ways to seat 4 women at 4 even places
`= .^(4)Pa = 4! = 24`
Again, no of ways to seat 5 men at 5 odd places `= .^(5)P_(5)`
`= 5! = 120`
Therefore, total possible ways `= 24 xx 120 = 2880`.