The vertical component of earth's magnetic field at a place is `sqrt3` times the horizontal component the value of angle of dip at this place is

Options

A. `30^(@)`
B. `45^(@)`
C. `60^(@)`
D. `75^(@)`

Answer

C

Explanation

`"As", B_(V)=sqrt3 B_(H)`
`"Also", tan delta=(B_(H))/(B_(H))=(sqrt3H)/(B_(H))=sqrt3 or delta=tan^(-1)(sqrt3)=60^(@)`
Angel of dip, `delta=60^(@)`