Home
Class 12
CHEMISTRY
Compelete reaction of 2.0 g calcium (at ...

Compelete reaction of 2.0 g calcium (at wt. = 40) with excess HCl produces 1.125 L of `H_(2)` gas. Complete reaction of the same wuantity of another metal "M" with excess HCl produces 1.85 L of `H_(2)` gas under identical conditions . The equivalent weight of "M" is closest to :

A

23

B

9

C

7

D

12

Text Solution

Verified by Experts

The correct Answer is:
D

`((eq)_(Ca))/((eq)_(M))=((eq)_(H_(2)),"released")/((eq)_(H_(2))," released")`
`((2/20))/((2/x))=((1.125)/(("eq.vol")H_(2)))/((1.85)/(("eq.vol".)H_(2)))" " {because"eq wt of M=X"}`
`:. x/20=1.125/1.85`
`x=1.125/1.85xx20~~12`
Promotional Banner

Topper's Solved these Questions

  • KVPY

    KVPY PREVIOUS YEAR|Exercise PART-1 CHEMISTRY|20 Videos
  • KVPY

    KVPY PREVIOUS YEAR|Exercise Matematics|1 Videos
  • KVPY

    KVPY PREVIOUS YEAR|Exercise Part B- Chemistry|10 Videos
  • KVPY 2021

    KVPY PREVIOUS YEAR|Exercise PART II CHEMISTRY|10 Videos

Similar Questions

Explore conceptually related problems

If 0.024 L of H_(2) gas is formed at the cathode, the volume of O_(2) gas formed at the anode under identical conditions, is:

Which of the following metals produce H_(2) gas on reaction with cold water?

The reaction between yttrium metal and dilute HCl produces H_(2) (g) and Y^(3+) ions. The molar ratio of yttrium to that hydrogen produced is

Volume of O_2 gas produced on electrolysis of dil. H_2SO_4 is 1120 mL The volume of H_2 produced in the same time is under identical conditions is

1g of a carbonate (M_(2)CO_(3)) on treatment with excess HCl produces 0.01186 mole of CO_(2) . The molar mass of M_(2)CO_(3) in g mol^(-1) is

1 gram of carbonate (M_(2)CO_(3)) on treatment with excess HCl produces 0.1186 mole of CO_(2) . The molar mass of M_(2)CO_(3) "in g mol"^(-1)