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The oxidation number of N and Cl in NOCl...

The oxidation number of N and Cl in `NOClO_(4)` respectively are

A

`+2 and +7`

B

`+3 and +7`

C

`-3 and +5`

D

`+2 and -7`

Text Solution

Verified by Experts

The correct Answer is:
B
`NOClO_(4)-=(NO^(+))(ClO_(4)^(-))` Let O.N. of N in `NO^(+)` is x
`:. x + (-2)=+1`
`x=3`
Let O.N of Cl in `ClO_(4)^(-)` is x
`:. x + 4 (-2)=-1 or x = +7`.
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