In which of the following reactions, the underlined substance has been oxidized ?

Options

A. `underline(Br_(2))+underline(H_(2)S)rarr2HBr+S`
B. `underline(2HgCl_(2))+SnCl_(2)rarrunderline(Hg_(2)Cl_(2))+SnCl_(4)`
C. `Cl_(2)+underline(2KI)rarr2KCl+ underline(I_(2))`
D. `2Cu^(+2)+4I^(-)rarrunderline(Cu_(2)I_(2))+I_(2)`

Answer

C

Explanation

In KI, I has O.N of -1. As it changes to `I_(2)`. The O.N increases from -1 to 0.