The oxidation states of sulphur in the anions `SO_(3)^(2-), S_(2)O_(4)^(2-)`, and `S_(2)O_(6)^(2-)` follow the order

Options

A. `S_(2)O_(6)^(2-) lt S_(2)O_(4)^(2-) lt SO_(3)^(2-)`
B. `S_(2)O_(4)^(2-) lt SO_(3)^(2-) lt S_(2)O_(6)^(2-)`
C. `SO_(3)^(2-) lt S_(2)O_(4)^(2-) lt S_(2)O_(6)^(2-)`
D. `S_(2)O_(4)^(2-) lt S_(2)O_(6)^(2-) lt SO_(3)^(2-)`

Answer

B

Explanation

Let O.S of S in `SO_(3)^(2-)` be x
`:. x + 3(-2)=-2`
`x=-2 +6 =4`
Let O.S. of S in `S_(2)O_(4)^(2-)` be x
`2x + 4(-2) =-2`
`2x = -2 +8`
`x=3`
Let O.S of S in `SO_(6)^(2-)` be x
`:. 2x +6(-2) =-2`
`2x = -2 +12`
`x = 15`
`:.` O.S of sulphur is in the order `S_(2)O_(4)^(2-) lt SO_(3)^(2) lt SO_(6)^(2-)`.