The oxidation number of sulphur in `H_(2)SO_(4),H_(2)S_(2)O_(4) and H_(2)S_(2)O_(6)` are respectively

Options

A. `+3,+4,+5`
B. `+5,+4,+3`
C. `+6,+3,+5`
D. `+3,+5,+4`

Answer

C

Explanation

O.N of S in `H_(2)SO_(4)` :
Let O.N. of S = x
`:. 2(+1)+x+4(-2)=0`
`rArr x = +6`
O.N of S in `H_(2)S_(2)O_(4)`
Let O.N. of S = x
`:. 2 (+1)+2x+4(-2)=0`
`rArr x = +3`
O.N of S in `H_(2)S_(2)O_(6)`
Let O.N of S = x
`:. 2(+1)+2x+6(-2)=0`
`rArr x = +5`.