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The oxidation states of the most electro...

The oxidation states of the most electronegative elements in the products of the reaction between `BaO_(2)` and `H_(2)SO_(4)` are

A

0 and -1

B

`-1 and -2`

C

`-2 and 0`

D

`-2 and +1`

Text Solution

Verified by Experts

The correct Answer is:
B, C
Reaction between `BaO_(2) and H_(2)SO_(4)` is
`BaO_(2)+H_(2)SO_(4)rarrBaSO_(4)+H_(2)O_(2)`
The most electron negative element in products in oxygen O.N of O in `BaSO_(4) and H_(2)O_(2)` is -2 and -1 respectively.
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