Home
Class 12
CHEMISTRY
A compound of Xe and F is found to have ...

A compound of Xe and F is found to have 53.5% Xe. What is the oxidation number of Xe in this comound?

A

`+2`

B

0

C

`+4`

D

`+6`

Text Solution

Verified by Experts

The correct Answer is:
D

`{:("Name of element","%age","At.mass","%Agr/At.mass","Simples ratio"),("Xe",53.3,133,(53.3)/(133)=0.398",",(0.398)/(0.398)=1),("F",46.7,19,(46.7)/(19)=2.45",",(2.45)/(0.398)=6):}`
`:.` Empirical formula `= XeF_(6)`
`:.` O.N. of Xe in `XeF_(6)=6`.
Promotional Banner

Topper's Solved these Questions

  • REDOX REACTIONS

    DINESH PUBLICATION|Exercise Assertion and Reason|7 Videos
  • PURIFICATION & CHARACTERISATION OF ORGANIC COMPOUND

    DINESH PUBLICATION|Exercise Ultimate Preparatory Package|15 Videos
  • SOLID STATE

    DINESH PUBLICATION|Exercise Brain storming|10 Videos

Similar Questions

Explore conceptually related problems

What is the oxidation number of Xe in XeOF_(2) ?

Oxidation number of Xe in XeF_(5)^(-) is :

The oxidation state of Xe in XeF_(6) is

Determine the oxidation number of Xe atom in Ba_2XeO_6

Xe shows oxidation states of

What is the Oxidation number of Xe in mixture of XeF_(6) and XeF_(4) ?