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If equal volumes of 1 M KMnO(4) and 1M K...

If equal volumes of 1 M `KMnO_(4)` and 1M `K_(2)Cr_(2)O_(7)` solutions are allowed to oxidise Fe(II) to Fe(III) in acidic medium, then Fe(II) oxidised will be

A

more by `KMnO_(4)`

B

more by `K_(2)Cr_(2)O_(7)`

C

equal in both the cases

D

can't be determined

Text Solution

Verified by Experts

The correct Answer is:
B
`overset(+7)(MnO_(4)^(-))+5e^(-)rarrMn^(2+)`
`overset(+6)(CrO_(4)^(2-))+6e^(-)rarr2Cr^(3+)`
Equal volumes of 1 M `KMnO_(4)` and 1M `K_(2)Cr_(2)O_(7)` have equal number of moles of `KMnO_(4) and K_(2)Cr_(2)O_(7)`. As 1 mole of `KMnO_(4)` accepts 5 moles of electrons and 1 mole of `K_(2)Cr_(2)O_(7)` accepts 6 moles of electrons, `K_(2)` will oxidise more `Fe^(2+)` to `Fe^(3+)`.
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