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The resistance of 0.01N solution of an e...

The resistance of 0.01N solution of an electrolyte AB at 328K is 100ohm. The specific conductance of solution is cell constant =`1cm^(-1)`

A

100ohm

B

`10^(-2)ohm^(-1)`

C

`10^(-2)ohm^(-1)cm^(-1)`

D

`10^(2)ohm-cm`

Text Solution

Verified by Experts

The correct Answer is:
C
Specific conductance
=Cell constan t `xx(1)/("resistance")`
`=1cm^(-1)xx(1)/(100"atm")`
`=10^(-2)ohm^(-1)cm^(-1)`
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