Home
Class 12
CHEMISTRY
For an electrolyte solution of 0.05 mol...

For an electrolyte solution of `0.05 mol L^(-1)`, the conductivity has been found to be `0.0110S cm^(-1)`. The molar conductivity is

A

`0.055S cm^(2)"mol"^(-1)`

B

`550 S cm^(2) "mol"^(-1)`

C

`0.22 S cm^(2) "mol"^(-1)`

D

`220S cm^(2)"mol"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D

`Lamda_m=(0.011xx1000)/(0.05)=220.5cm^(2)"mol"^(-1)`
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    DINESH PUBLICATION|Exercise REVISION QUESTIONS FROM COMPETITIVE EXAMS|198 Videos
  • ELECTROCHEMISTRY

    DINESH PUBLICATION|Exercise SELECTED STRAIGHT OBJECTIVE|67 Videos
  • D-AND -F BLOCK ELEMENTS

    DINESH PUBLICATION|Exercise BRAIN STORMING MULTIPLE CHOICE QUESTIONS (MCQS)|13 Videos
  • ETHERS

    DINESH PUBLICATION|Exercise (MCQs)|8 Videos

Similar Questions

Explore conceptually related problems

The specific conductivity of a solution containing 1.0g of anhydrous BaCI_(2) in 200 cm^(3) of the solution has been found to be 0.0058 S cm^(-1) . Calculate the molar and equivalent conductivity of the solution. Molecular wt. of BaCI_(2) = 208 [mu implies lambda_(m)]

The conductivity of 0.35M solution of KCl at 300K is 0.0275 S cm^(-1) . Calculate molar conductivity

The conductivity of 0.20 M KCl solution at 298 K is 0.025 S cm^(-1) . Calculate its molar conductivity .

The conductivity of 0.25 M solution of KCI at 300 K is 0.0275 cm^(-1) calculate molar conductivity