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Given that I(2)+2e^(-)rarr2I^(-): E^(@)=...

Given that `I_(2)+2e^(-)rarr2I^(-): E^(@)=0.54V`
`Br_(2)+2e^(-)rarr2Br^(-):E^(@)=1.09V`
Predict which of the following is true

A

`I^(-)` ions will be able to reduce bromine

B

`Br^(-)` will be able to reduce iodine

C

Iodine will be able to reduce bromide ions

D

Bromine will be able to reduce iodide ions

Text Solution

Verified by Experts

The correct Answer is:
A
Since `E^(@)` value of `Br_(2)//Br^(-)` is higher, Hence `I^(-)` ions will reduce `Br_(2)` to `Br^(-)` ions.
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