The e.m.f. of the cell
`Ti|Ti^(+)(0.001M)||Cu^(2+)(0.01M)|Cu` is 0.83V the emf of this cell could b e increased by

Options

A. increasing the concentration of `Ti^(+)` ions
B. increasing the concentration of `Cu^(2+)` ions
C. increasing the concentration of both
D. none of the above.

Explanation

To solve the problem regarding the increase of e.m.f. (electromotive force) of the cell `Ti|Ti^(+)(0.001M)||Cu^(2+)(0.01M)|Cu`, we will use the Nernst equation and analyze the cell reactions.

### Step-by-Step Solution:

1. **Identify the Cell Components**:
- Anode: Titanium (Ti) is oxidized to Ti²⁺.
- Cathode: Copper ions (Cu²⁺) are reduced to copper (Cu).

2. **Write the Half-Reactions**:
- Oxidation at the anode:
\[ \text{Ti} \rightarrow \text{Ti}^{2+} + 2e^- \]
- Reduction at the cathode:
\[ \text{Cu}^{2+} + 2e^- \rightarrow \text{Cu} \]

3. **Overall Cell Reaction**:
- Combining the half-reactions gives:
\[ 2\text{Ti} + \text{Cu}^{2+} \rightarrow 2\text{Ti}^{2+} + \text{Cu} \]

4. **Determine the Reaction Quotient (Q)**:
- The reaction quotient \( Q \) is given by:
\[ Q = \frac{[\text{Ti}^{2+}]^2}{[\text{Cu}^{2+}]} \]
- Given concentrations are:
- \([\text{Ti}^{2+}] = 0.001 \, M\)
- \([\text{Cu}^{2+}] = 0.01 \, M\)
- Therefore,
\[ Q = \frac{(0.001)^2}{0.01} = \frac{0.000001}{0.01} = 0.0001 \]

5. **Apply the Nernst Equation**:
- The Nernst equation is:
\[ E_{\text{cell}} = E^\circ_{\text{cell}} - \frac{0.0591}{n} \log Q \]
- Where \( n = 2 \) (number of electrons transferred).
- Substituting the values:
\[ E_{\text{cell}} = 0.83 - \frac{0.0591}{2} \log(0.0001) \]

6. **Calculate the Logarithm**:
- \(\log(0.0001) = -4\)
- Therefore,
\[ E_{\text{cell}} = 0.83 - \frac{0.0591}{2} \times (-4) \]
\[ E_{\text{cell}} = 0.83 + 0.1182 = 0.9482 \, V \]

7. **Determine How to Increase E.m.f.**:
- From the Nernst equation, to increase \( E_{\text{cell}} \), we can:
- Decrease the concentration of the reactants (in this case, \( \text{Ti}^{2+} \)).
- Increase the concentration of the products (in this case, \( \text{Cu}^{2+} \)).
- Therefore, increasing the concentration of \( \text{Cu}^{2+} \) will lead to an increase in the e.m.f. of the cell.

### Conclusion:
The e.m.f. of the cell can be increased by **increasing the concentration of Cu²⁺ ions**.