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The half-cell reduction potential of a h...

The half-cell reduction potential of a hudrogen electrode at `pH= 10` will be.

A

0.59V

B

`-0.59V`

C

Zero votls

D

`-0.059V`

Text Solution

Verified by Experts

The correct Answer is:
B
`E=0+(0.059)/(1)"log"[H^(+)]`
`=0+0.059"log"10^(-10)`
`0.059xx(-10)=-0.59V`.
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