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The EMF of a cell is related to the equi...

The EMF of a cell is related to the equilibrium constant of the cell reaction as

A

In `k_(c)=(nFE_("cell")^(@))/(RT)`

B

`k_(c)=(nFE_("cell")^(@))/(RT)`

C

`E_("cell")^(@)=(RT)/(nF)` in `k_(c)`

D

`k_(c)=(RT)/(nF)` in `E_("cell")^(@)`

Text Solution

Verified by Experts

The correct Answer is:
A
`E_("cell")^(@)=-nFE^(@)`
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