Home
Class 12
CHEMISTRY
For a reaction A(s)+2B^(+) rarr A^(2+)+2...

For a reaction `A(s)+2B^(+) rarr A^(2+)+2B`
`K_(c)` has been found to be `10^(12)`. The `E_(cell)^(@)` is

A

`0.354V`

B

`0.708V`

C

`0.0098V`

D

`1.36V`

Text Solution

Verified by Experts

The correct Answer is:
A
`DeltaG=-RT` in `k_(c)`
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    DINESH PUBLICATION|Exercise REVISION QUESTIONS FROM COMPETITIVE EXAMS|198 Videos

  • ELECTROCHEMISTRY

    DINESH PUBLICATION|Exercise SELECTED STRAIGHT OBJECTIVE|67 Videos

  • D-AND -F BLOCK ELEMENTS

    DINESH PUBLICATION|Exercise BRAIN STORMING MULTIPLE CHOICE QUESTIONS (MCQS)|13 Videos

  • ETHERS

    DINESH PUBLICATION|Exercise (MCQs)|8 Videos

Similar Questions

Explore conceptually related problems

For a reaction A(s)+2B^(o+) rarr A^(2+)+2B K_(c) has been found to be 10^(12) . The E^(c-)._(cell) is

For a reaction A(s) + 2B^(+) rarr A^(2+)+2B(s). K_(c) has been found to be 10^(14) The E^(o) ""_(cell) is :

For a reaction A(s)+2B^(+) (aq) rarr A^(2+) (aq) rarr A^(2+)(aq)+2B, K_(C) has been found to be 10^(12) . The E_("cell")^(@) is 0.354 V

The equilibrium constant (K) for the reaction Cu(s)+2Ag^(+) (aq) rarr Cu^(2+) (aq)+2Ag(s) , will be [Given, E_(cell)^(@)=0.46 V ]

For the redox reaction: Zn(s) +Cu^(2+) (0.1M) rarr Zn^(2+) (1M)+Cu(s) taking place in a cell, E_(cell)^(@) is 1.10 volt. E_(cell) for the cell will be (2.303 (RT)/(F) = 0l.0591)

Given the equilibrium constant : K_(C) of the reaction: Cu(s) + 2Ag^(+)(aq) to Cu^(2+) + 2Ag(s) is 10xx 10^(15) , calculate the E_("cell")^(ө) of this reaction at 298 K [2.303(RT)/(F) at 298 K = 0.059V]