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The free energy change in related to equ...

The free energy change in related to equilibrium constant as

A

`DeltaG=RT` in `k_(c)`

B

`-DeltaG=RT "log" k_(c)`

C

`-DeltaG=2.303 Rt "log" k_(c)`

D

`-DeltaG=(RT"log"k_(c))//2.303`.

Text Solution

Verified by Experts

The correct Answer is:
C
`-DeltaG=2.303 Rt` log `k_(c)`
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