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At 298 K the resistance of a 0.1M KCl so...

At 298 K the resistance of a 0.1M KCl solution is found to be 39.0ohm. If the conductivity (k) of this solution is 1.29`xx10^(-2)ohm^(-1)cm^(-1)` at 298K, what is cell contant

A

`5.03xx10^(-1)cm^(-1)`

B

`10.06xx10^(-1)cm^(-1)`

C

`15.09xx10^(-1)cm^(-1)`

D

`2.51xx10^(-1)cm^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
The cell cosntnat =l/a=R.k
=39 ohm 1.29`xx10^(-2) ohm^(-1)cm^(-1)`
`=5.03xx10^(-1)cm^(-1)`
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