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At 298K the electrolytic conductivity o...

At 298K the electrolytic conductivity of a 0.2 M KCl solution is `2.5xx10^(-2) ohm^(-1)cm^(-1)` compute its molar c onductivity.

A

62.5`ohm^(-1) cm^(2)"mol"^(-1)`

B

`125ohm^(-1)cm^(2)"mol"^(-1)`

C

`250ohm^(-1)cm^(2)"mol"^(-1)`

D

`175ohm^(-1)cm^(2)"mol"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
Molar conducitivity `=(1000K)/(C) ohm^(-1)cm^(2)"mol"^(-1)`
`=(1)/(100)xx0.037=3.7xx10^(-4)ohm^(-1)cm^(-1)`
`therefore `Molar conductivity `=(1000xx3.7xx10^(-4))/(0.05)`
`=7.4ohm^(-1)cm^(2) "mol"^(-1)`
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