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When 2 Faraday of electricity is passed ...

When 2 Faraday of electricity is passed in an aqueous solution of cupric sulphate, the amount of copper deposited on cathode is

A

63.5g

B

127.0g

C

31.75g

D

250g

Text Solution

Verified by Experts

The correct Answer is:
A
In `CuSO_(4).Cu^(2+)+2e^(-)rarrCu`
`therefore Eq. wt. "of" Cu=(63.2)/(2)=31.75`
Now `1F=31.75g "of" Cu`
`2F=31.75xx2=63.5g`
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