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When the electrolytis of silver sulphate...

When the electrolytis of silver sulphate was carried out by Pt electrodes. 1-6 g oxygen was liberated at the anode, the amount of silver deposited at cathode will be

A

108g

B

1.6g

C

21.6 0g

D

0.8g

Text Solution

Verified by Experts

The correct Answer is:
C
`("Mass of oxygen")/("Mass of silver")=("Eq. wt. of oxygen ")/("eq. wt. of silver")`
`(1.6 g)/(m)=(8)/(108)`
or `m=(108xx1.6)/(8)=21.6g` of Ag.
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