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Number of moles of oxygen liberated by e...

Number of moles of oxygen liberated by electrolysis of 90g of water

A

9 moles

B

4-5 moles

C

2.5moles

D

5 moles.

Text Solution

Verified by Experts

The correct Answer is:
c
Electrolysis of water
`2H_(2)Ooverset("Electrolysis")rarr2H_(2)+O_(2)`
`therefore 2` mol `H_(2)O=1` mol of `O_(2)`
and 5 mol `H_(2)O=(1)/(2)xx5=2.5` mol of `O_(2)`
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