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Calculate the equilibrium constant for t...

Calculate the equilibrium constant for the reaction `Cu(s)+2Ag^(+)(aq)rarrCu^(2+)(aq)+2Ag(s), E_(cell)^(@)=0.46 V`.

A

`579jK^(-1)`

B

`386jK^(-1)`

C

`193jK^(-1)`

D

None of these.

Text Solution

Verified by Experts

The correct Answer is:
B
`DeltaS^(@)=nF((dE^(@))/(dT))_(p)`
`=2xx96500((0.48-0.46)/(310-300))`
`=(2xx96500xx0.02)/(10)=386JK^(-1)`
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