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When E(Ag)^(@)+(//Ag)=0.8V and E(Zn^(@...

When `E_(Ag)^(@)+_(//Ag)=0.8V` and ` E_(Zn^(@))2^(+)._(//Zn)`
`=-0.76V`. Which of the following is correct?

A

`Ag^(+)` can be reduced by `H_(2)`

B

`Ag` can oxidise `H_(2)` into `H^(+)`

C

`Zn^(2+)` can be reduced by `H_(2)`

D

Ag can reduce `Zn^(2+)` ion.

Text Solution

Verified by Experts

The correct Answer is:
A
Zinc has lower red pot, than hydrogen and hence can be reduced. Ag has more reduction potential so it is reduced easily.
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