The resistance of `1N` solution of acetic acid is `250ohm`, when measured in a cell of cell constant `1.15 cm^(-1)`. The equivalent conductance `(` in `ohm^(-1) cm^(2)eq^(-1))` of `1N` acetic acid is

Options

A. 4.6
B. 9.2
C. 18.4
D. 0.023

Answer

A

Explanation

Conductivity `(k)=(1)/(R)xx`Cell constant
`=(1)/(250)xx1.15`
`^^_(eq)=(kxx1000)/(N)=(1.15)/(250)xx(1000)/(1.0)`
`=4.6 ohm^(-1) cm^(2) eq^(-1)`