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For the cell reaction Cu^(2+)(C(1),aq....

For the cell reaction
`Cu^(2+)(C_(1),aq.)+Zn(s)hArrZn^(2+)(C_(2),aq)+Cu(s)`
of an electrochemical cell, the change in free energy `(DeltaG)` of a given temperature is a function of

A

In `(C_(1))`

B

`In(C_(2)//C_(1))`

C

`In (C_(1)+C_(2))`

D

`In(C_(2))`

Text Solution

Verified by Experts

The correct Answer is:
B
`DeltaG=-nFE "and" E=E^(@)-(RT)/(nF)"In"(C_(2))/(C_(1))`
(Here n=2)
`DeltaG` is a function of E and E is a function of in `(C_(2)//C_(1))`
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