Same amount of electric current is passed through solutions of `AgNO_(3)` and HCl. If 1.08 g of silver is obtained in the first case, the amount of hydrogen liberated at S.T .P. in the second case is:

Options

A. `112cm^(3)`
B. `22400cm^(3)`
C. `224cm^(3)`
D. `1.008g`.

Answer

A

Explanation

`("Mass of Ag")/("Mass of " H_(2))=("Eq. mass of Ag")/("Eq. mass of " H_(2))`
`(1.08)/("mass of" H_(2))=(108)/(1)`
Mass of `H_(2)=( 1.08)/(108)=10^(-2)g`
2g of `H_(2)` at S.T.P. occupy 22400 `cm^(3)`
`therefore10^(-2)g` of `H_(2)` at STP occupy
`=(22 400)/(2)xx10^(-2)10^(-2)cm^(3)=112cm^(3)`