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Time required to deposit one milli"mole"...

Time required to deposit one milli"mole" of aluminium metal by the passage of 9.65 amp through aqueous solution of aluminium ion is:

A

30s

B

10s

C

30,000s

D

10,000s.

Text Solution

Verified by Experts

The correct Answer is:
A
1 mol of Al requires =3xx96500C
`10^(-3)` mol of Al requires `=3xx96500xx10^(-3)C`
`=3xx96.5C`
`therefore` Time (s)`=(3xx96.5As)/(9.65A)=30s`
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