Aluminium displaces hydrogen from dilute HCl whereas silver does not. The e.m.f. of a cell prepared by combining `Al//Al^(3+)` and `Ag// Ag^(+)` is 2.46V. The reduction potential of silver electrode is +0.80V. The reduction potential of aluminium electrode is

Options

A. `+1.66V`
B. `-3.26V`
C. `3.26V`
D. `-1.66V`

Answer

D

Explanation

`Al|Al^(3+)||Ag^(+)|Ag`
`E=E_(Ag^(+)._(//Ag))-E_(Al^(3+)._(//Al))`
`E_(Al^(3+_(//Al))=0.80-2.46=-1.66V`