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The standard EMF of a galvanic cell invo...

The standard `EMF` of a galvanic cell involving cell reaction with `n=2` is found to be `0.295 V` at `25^(@)C` . The equilibrium constant of the reaction would be

A

`1.0xx10^(10)`

B

`2.0xx10^(11)`

C

`4.0xx10^(12)`

D

`1.0xx10^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`E^(@)=(0.0591)/(n)"log" k_(c)`
`0.295=(0.0591)/(2)"log"k_(c)`
`"log" k_(c)=(0.295xx2)/(0.0591)`
`"log" k_(c)=9.9830`
`k_(c)="antilog" 9.9830=10^(10)`
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