The hydrogen electrdoe is dipped in a solution of pH=3 at `25^(@)C` the potential of the cell would be (the value of 2.303 RT/F is 0.059 V)

Options

A. 0.177V
B. 0.087V
C. `-0.177V`
D. `0.059V`

Answer

C

Explanation

`pH=3`
`therefore [H^(+)]=10^(-3)`
`H^(+)+e^(-)rarr(1)/(2)H_(2)`
`E=E^(@)-(0.059)/(n)"log" (1)/([H^(+)])=0-(0.059)/(1)"log"10^(3)`
` E=-0.177V`