The standard e.m.f. of a cell involving one electron charge is found to be 0.591V at `25^(@)C` the equilibrium constant of the reaction is (F=96500C `"mol"^(-1)`:R=8.314 `JK^(-1)"mol"^(-1)`)

Options

A. `1.0xx10^(1)`
B. `1.0xx10^(30)`
C. `1.0xx10^(10)`
D. `1.0xx10^(5)`

Answer

C

Explanation

At 298
`E^(@)=(0.0591)/(n)"log" k_(c)`
`0.591=(0.0591)/(1)"log"K_(c)`
`"log" k_(c)=(0.5910)/(0.0591)`
` "log"k_(c)=10`
`K_(c)=10^(10)`